Mark M. answered 04/06/15
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Retired math prof. Very extensive Precalculus tutoring experience.
A parabola opening downward with x-coordinate of vertex halfway between x = -1 and x = 5 and with y-coordinate 9 would work.
So, vertex = (2, 9)
Equation of parabola: y = A(x+1)(x-5). Find A so that y = 9 when
x = 2
9 = A(3)(-3) A = -1
y = -(x+1)(x-5)
y = -(x2 - 4x - 5)
y = -x2 + 4x + 5