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_Na + _H3PO4 ->

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If you are dealing with net ionic equations, you would write:

   6 Na(s)  +    2 H3PO4(aq)  -->   3H2(g)  +  6 Na+  +  2 PO43-   

To start things off, you should recognize what type of reaction is taking place. In this case, it's a single replacement reaction. This means that sodium atoms are replacing the hydrogen atoms. A phosphate ion has an ionic charge of -3 while a sodium ion has a charge of +1. Therefore there will be three sodium ions per phosphate ion.

So now we can predict the products of the reaction: Na + H3PO4 -> Na3PO4 + H2

However, the reactants and products still need to be balanced so there is no loss or gain of atoms throughout the reaction.

After balancing, the answer should be: 6 Na + 2 H3PO4 -> 2 Na3PO4 + 3 H2