1 Answered Questions for the topic Pre-calculus, Difference Quotient
Pre Calculus, difference quotient
04/20/17
Question about difference quotient with exponents (pre-calculus)
If f(x) = 10^x, show that:f(x+h) - f(x)/h = 10^x[(10^h - 1)/h] f(x+h) - f(x)/h = 10^x[(10^h - 1)/h] As a function of x, the difference quotient of 10^x is 10^x multiplied by a constant. I have been...
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