We can solve for the change in entropy for the water using the equation ΔS = Q/T, where ΔS is change in entropy, Q is the heat transferred (in J), and T is the temperature (in K).
If 1kJ of thermal energy is leaving the reservoir, the reservoir has a Q = -1kJ.
Think about why this is a negative number -- is the energy leaving or entering the system?
Q = -1kJ = -1000J
Convert the temperature from °C to K by adding 273.15:
T = 500°C = 773K
Now plug Q and T into the equation ΔS = Q/T
ΔS = Q/T
ΔS = -1000J / 773K = -1.29 J/K