Solve a question of trigonometry function

Question

d the solutions of the equation in the interval[ -2 pi, 2 pi] use a graphing utility to verify your results.

Csc(x)= 2 (3)^(1/3)/3

Answer 1

cscx = (2/3)3^(1/3)=about .9615 =1/sinx which is impossible as that makes a sine >1 and all sines are never >1

there's a problem with the problem, miscopied or maybe misprinted, a typo maybe

Answer 2

I agree with the comment from Doug

If cscx=(2/3)3^1/2

then sinx=(3/2)3^-1/2=(3/2)(3^1/2/3)=3^1/2/2

in domain [-2π,2π]

x=-5π/3,-4π/3,π/3,2π/3 would result in cscx=(2/3)3^1/2