I need to know how to solve this quadratic equation. I am supposed to answer it by completing the square.

x^2-2x-2=0

I need to know how to solve this quadratic equation. I am supposed to answer it by completing the square.

x^2-2x-2=0

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When completing you must isolate the terms that have x.

x^{2} - 2x = 2

Then you take the coefficient of the "b" term (2x), divide it by 2 and then square it giving you the result of 1. You then add that to both sides so your equation should now read

x^{2} - 2x + 1 = 3

Now simply factor and solve!

(x-1)(x-1) = 3

x - 1 = sqrt(3)

x= sqrt(3) + 1

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