Find an equation of the circle that satisfies the given conditions. Center (−2, 9); passes through (−4, −3)

Answer 1

center (-2,9) through (-4,-3)

(x+2)^2 + (y-9)^2 = r^2

plug in the point to solve for r^2

(-2)^2 + (-12)^2 = 4+144= 148 = r^2

circle's equation is

(x+2)^2 + (y-9)^2 = 148

Answer 2

The graph of (x-h)² + (y-k)² = r² is the circle with center (h,k) and radius r.

So, we have (x + 2)² + (y - 9)² = r², where r is the distance from the center to any point on the circle.

r = √[(-4 - (-2))² + (-3 - 9)²] = √148

Equation of the circle is (x + 2)² + (y - 9)² = 148.