If a mine pony had to perform a task where they had to lift a bucket of ore 20 m from the bottom of

Question

If a mine pony had to perform a task where they had to lift a

bucket of ore 20 m from the bottom of the shaft to the top of the shaft, what would the

reduction in force be if a ramp was used that is 10 m long? What would be the power

requirement if the job took 30 seconds?

Answer 1

There is something wrong with the numbers. A 10 m long ramp cannot be used to raise something 20 m. If it was a 100 m ramp, then the ideal work is Fd for both the straight up lift and up the ramp leading to

F_R/F_SU= (d_SU/d_R) or 1/5 (The IMA is 5)

You can't find the power requirement without the mass of the ore

P = mgh/t

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