
William W. answered 05/09/24
Experienced Tutor and Retired Engineer
Assuming (as inferred) that the spring is the same length as the barrel:
The velocity of 4 m/s as the dart leaves the barrel means we can calculate its kinetic energy:
EK = (1/2)mv2 = (1/2)(0.030)(4.0)2 = 0.24 joules
When compressed, the spring would need to provide the same value of potential energy (the spring's potential energy gets converted to kinetic energy as the dart reaches the end of the barrel).
Spring Potential energy is calculated as:
ESP = (1/2)kx2 = (1/2)(k)(8/100)2 = 0.0032k joules
Since EK = ESP then 0.24 = 0.0032k so k = 75 N/m