Image height and position with a diverging lens.

Question

A 4.0-cm-tall object is 17 cm in front of a diverging lens that has a -30 cm focal length.

Calculate the image position.

Calculate the image height.

Answer 1

1/F = 1/d + 1/f; -1/30 = 1/17 + 1/f ; f = - 30·17/47 = - 10.851 cm

1. means that image located in front of lens
2. h/4 = 10.851/17; h = 2.5532 cm
3.