Yefim S. answered  05/06/24
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-1/9 = 1/18 + 1/f; f = - 6 cm. So, the image on the same side from lense as object
Lauren M.
asked  05/06/24A diverging lens with focal length 9.00 cmcm is 18.0 cmcm from an object. What is the image distance s′𝑠′?
Yefim S. answered  05/06/24
Math Tutor with Experience
-1/9 = 1/18 + 1/f; f = - 6 cm. So, the image on the same side from lense as object
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