A bicycle wheel with radius 0.3 m rotates from rest to 2.1 rev/s in 5.3 s. What is the magnitude (in m/s2) of the total acceleration vector at the edge of the wheel at 2.0 s?

Answer 1

2.1 rev/s x 2π radians/rev = 13.195 rad/s (final angular velocity or ω_f)

(13.195 rad/s)/5.3 s) = 2.49 rad/s² (average angular acceleration or α)

Average tangential acceleration (a_T) = r•α = (0.3)(2.49) = 0.747 m/s²

Magnitude of total acceleration vector = √(a_T² + α²) = √(0.747² + 2.49²) = √6.76 = 2.6 m/s²