A block mass 12.2 kg sitting on ramp that makes angle 24 degrees with the horizontal. The block is being pushed by horizontal force 214N. The coefficient kinetic friction between the two surfaces 0.46

Question

Find the acceleration of the block up the ramp in m/s^2

Answer 1

-mgsin24° + Fcos24° - f = ma; f = 0.46(Fsin24° + mgcos24°) = 0.46(214Nsin24° + 12.2kg·9.81m/s²) =

= 95.093 N; a = (214cos24° - 12.2·9.81sin24° - 95.093)/12.2 = 4.24 m/s²