Physicis Change in heat temp

Question

The specific heat capacity of steel is 450 J/kg⋅∘CJ/kg⋅∘C. Find the amount of heat that is needed to raise the temperature of a 13-kgkg piece of steel from 0 ∘C to 130 ∘C.

How does this compare with the heat needed to raise the temperature of the same mass of water through the same temperature difference? (For water, c = 4190 J/kg⋅∘CJ/kg⋅∘C.)

Answer 1

Use the equation:

where "Q" is the heat, "m" is the mass, C_p is the specific heat capacity, and ΔT is the temperature difference (T₂ - T₁)

For the steel:

Q = (13)(450)(130 - 0) = 760500 joules or 760 kJ

For the water:

Q = (13)(4190)(130 - 0) = 7081100 joules or 7080 kJ