With the aid of a string, a gyroscope is accelerated from rest to 30 rad/s in 0.8 s. How many revolutions does it go through in the process?

Answer 1

φ = (0 + ω)/2·t = 30/2rad/s·0.8s = 12rad; n = φ/(2π) = 12/(2π) = 1.91 rev