Yefim S. answered 03/27/24
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Math Tutor with Experience
Q = mLf = 48g·80cal/g = 3840 cal
Willowanne C.
asked 03/27/24Heat of fusion : Q=mLf
Find what heat in calories (calcal) is needed to melt 48 gg of 0∘C∘C ice. The heat of fusion Lf�� for water is 80 cal/gcal/g.
Yefim S. answered 03/27/24
Math Tutor with Experience
Q = mLf = 48g·80cal/g = 3840 cal
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