Physics - Temperature change

Question

A 130-gg chunk of 90 ∘C∘C iron is dropped into a cavity in a very large block of ice at 0∘C What is the mass of ice that melts? (The specific heat capacity of iron is 0.11 cal/g⋅∘Ccal/g⋅∘C.)

Answer 1

mc(t - 0) = Mλ; M = mct/λ = 130g·0.11cal/(g·°C)·90°C/79.8cal/g = 16.13 g