Solve by the substitution method.

Question

y-3x=16

9y+x=32

 

What is the solution of the system?

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(Type  an order pair.)

Answer 1

Hi Hunter,

 

y-3x =16

y = 16 +3x........ eqn 1

 

9y +x = 32..... eqn 2

 

substituting value of y from eqn 1 to eqn 2, we get,

 

9(16+3x) +x =32

144 +27x +x = 32

28x = 32-144

28x = -112

x = -112/28 -4

 

now substituting the value of x=-4 in eqn 1,we get,

y = 16 + 3(-4) = 16 -12= 4

 

(-4,4)