Muhammad Nabeel R. answered • 02/24/24
All Students can succeed with a little Help!
First, you've mentioned that the light energy falling on a square meter of ground over a typical sunny day is about 20 MJ. This is equivalent to 20,000,000 Joules (1 MJ = 1,000,000 J).
Now, you know that the conversion efficiency of solar cells is 17%. This means that only 17% of the light energy is converted into electric energy. Therefore, the electric energy produced per square meter of ground is:
Eelectric=Efficiency×Elight
Eelectric=0.17×20,000,000 J
Eelectric=3,400,000 J
Next, you've mentioned that the average rate of electric energy consumption in one house is 1.0 kW. This is equivalent to 1,000 Watts.
Now, to find out how much energy one house uses during a 24-hour day, you can use the formula:
Energy=Power×Time
Energy=1,000W×24h
Energy=24,000Wh
Now, you mentioned that this value is equal to 8.6×10^7 J, so:
24,000Wh=8.6×10^7
J
Now, we can find out how many houses can be powered by the electric energy produced per square meter of ground:
Number of houses=Eelectric per square meter / Energy per house per day
Number of houses=3,400,000 J / 8.6×10^7 J per house
Number of houses≈0.0395
Now, you mentioned that you want to supply electrical energy for 350,000 houses. So, the total area needed is:
Total area=Number of houses / Houses per square meter
Total area=350,000 / 0.0395 square meters
Total area≈8,860,759 square meters
Now, convert this to square miles (1 square mile = 2.58999 × 10^6 square meters):
Total area in square miles≈8,860,759 / 2.58999×10^6
Total area in square miles≈3.42 square miles
Therefore, approximately 3.42 square miles of land must be covered with solar cells to supply the electrical energy for 350,000 houses.
I hope that will help you!! Dear Regards!!
