A car's constant velocity is 28 m/s, a moose is 75 m ahead. The brakes are applied, the car accelerates at – 6.4 m/s . What was the maximum reaction time the driver had to apply the brakes?

Answer 1

v = 28 - 6.4t = 0; t = 28.6.4 = 4.375 s; Distance for this time: d = 28·4.375 - 3.2·4.375² = 61.25 m So, max reaction time is (75 - 61.25)/28 = 0.491 s