Physic question

Question

A physic student stand on a cliff overlooking a lake and decides to throw a softball to her friends in the water below. she throws the softball with a velocity of 24.5 m/s at an angle of 34.5 degrees above the horizontal. when the softball leaves her hand it is 15.5 m above the water. How far X does the softball travel horizontally before it hits the water? ( neglect any effects of air resistance when calculation the answer.)

Answer 1

x = 24.5cos34.5°·t; y = 15.5 + 24.5sin34.5°·t - 4.9t² = 0; t = 3.69 s; x = 24.5cos34.5°·3.69 = 74.5 m