Plsssss help, sorry for the trouble

Question

A 3.6 kg bowling ball is dropped from a height of 1.4 m falls onto a spring with and compresses 57.9 cm. Solve for the spring constant (k).

Answer 1

To solve this we need to use conservation of energy, our known parameters are 3.6 kg ball, 1.4 meter height, and a spring compression of 57.9 cm.

The ball has potential energy at the top, which can be expressed as

PE = (height)*(Mass)*(Gravity)

At the bottom, it will compress the spring equal to the potential energy it has.

The expression for the energy in a compressed spring is

PE = (1/2)*(K constant)*(displacement)²

Set these equal to each other and solve for K.

k = (2*M*G*H) /(x²)

k = 294.67 (N/m) Newtons per meter