
Lily F.
asked 01/28/24calculate the amount of work done on the system from 0-2 and then for the entire curve from 0-5 given the volume and pressure.
a pressure versus volume diagram for a system is shown in the figure. the values for the points in the diagram are shown in the table (couldn't include the image. points 0,1,2 make a triangular region. points 2,3,4 make a rectangular region. points 4,5 make a triangular region. if that helps)
calculate the amount of work done on the system from 0-2 and then for the entire curve from 0-5 given the volume and pressure.
volume: pressure:
v0 = 25.4 p0 = 1.37 x 10^4
v1 = 19.3 p1 = 1.37 x 10^4
v2 = 16.8 p2 = 5.76 x 10^3
v3 = 13.9 p3 = 5.76 x 10^3
v4 = 13.9 p4 = 2.78 x 10^3
v5 = 8.36 p5 = 1.57 x 10^3
1 Expert Answer
Ariel B. answered 01/29/24
PhD (Physical Chemistry), MS (Theoret.Physics), 10+ yr. tutor. exp.
Hi Lily,
There are 4 regions (4processes) here
0 to 1: isobaric W=Po(V1-Vo)
1 to 2: (process known by the P(V) linear so it forms a trapezoid with area (which is equal to work)
W=1/2(p1+p2)(V2-V1)
2 to 3 isobaric: W=P2(V3-V2)
3 to 4 isochoric: W=0
4 to 5 : again, a trapezoidal graph : W=1/2(p4+p5)(V4-V5)
Work from 0 to 2 is the sum of works from 0 to1 & from 1 to 2. In a similar way you'd find the work on the rest of the path (2 to 5) and therefore on the whole path 0 to 5
Hope it'd help
Best
Dr.Ariel B.
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Stanton D.
Just calculate the change in p*V for each step. Each of those is a work term, add them together. (All the .delta.pV's are negative). Incidentally, that work is removed as heat, it would appear ....01/29/24