Speed and Velocity

Question

A particle travels horizontally between two parallel walls separated by 18.4 m. It moves toward the opposing wall at a constant rate of 8.9 m/s. Also, it has an acceleration in the direction parallel to the walls of 4.4 m/s 2.

A. What will be its speed when it hits the opposing wall? Answer in units of m/s.

B. At what angle with the wall will the particle strike? Answer in units of ◦ .

Answer 1

Time t = s/v = 18.4/8.9 m/s = 2.07 s

A. Speed v = (8.9² + 4.4²·2.07²)^1/2 = 12.7 m/s

B. tanθ = 18.4/(4.4·2.07); θ = tan^-1(18.4/4.4·2.07) = 63.66°