Oziel T. answered 01/27/24
Patient and Understanding Math Tutor with High Expertise
Here is the explanation to these two problems. Sorry for the lengthy video. I wanted to clearly explain how to do this. I hope this helps!

Eric S.
asked 01/26/24having a hard time getting a few questions answered and understanding how to get the correct answers.
Expand the logarithm as much as possible. Rewrite the expression as a sum, difference, or product of logs.
ln(1/25^k)
Enclose arguments of functions in parentheses and include a multiplication sign between terms. For example, c*ln(h).
2. second question:
Use the properties of logarithms to expand the logarithm as much as possible. Rewrite the expression as a sum, difference, or product of logs.
log(√x^3y^-4)
Oziel T. answered 01/27/24
Patient and Understanding Math Tutor with High Expertise
Here is the explanation to these two problems. Sorry for the lengthy video. I wanted to clearly explain how to do this. I hope this helps!
Mark M. answered 01/26/24
Retired math prof. Very extensive Precalculus tutoring experience.
ln(1 / (25)k) = ln(1) - ln(25)k = 0 - k ln(25) = -kln(25)
log(√(x3) y-4) = log(√x3) + log(y-4) = log(x3/2) + log(y-4) = (3/2)logx - 4logy
Bradford T.
You could continue with the first one using 25=5^2 to get -2kln(5)01/26/24
Eric S.
Thank you for your response. I tried plugging those answers in to complete the questions with those answers and it is not taking them as the correct answer. I will try again later but I don't know if maybe I am just inputting the information incorrectly.01/27/24
Oziel T.
01/27/24
Mark M.
01/27/24
Brenda D.
01/27/24
Eric S.
I will check again on both I am pretty sure I copied the both problems to each question the way that I was given but I will recheck since the response answers came up not correct. I could be missing something myself.01/28/24
Eric S.
I just checked and the First problem does put the problem to solve as ln(1/25^k) and yes I tried putting in the answer of -k*ln(25) and also tried -2k*ln(5). Neither answer was correct. No limit on how many attempts I can try and the question for the first problem is exactly written down exactly as it is given.01/28/24
Eric S.
for the second question the equation that I need to resolve is indeed log(square root of x^3y^-4) which is also is not taking the answer given as correct.01/28/24
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Brenda D.
01/27/24