John R. answered 04/05/13
John R: Math, Science, and History Teacher
Assuming that the canoes were at rest when they were pushed apart, the total momentum in the system must be zero. This means that the momentum of canoe 1 must have the same magnitude as the momentum of canoe 2, but in opposite directions.
p1 = -p2
m1v1 = -m2v2
m1v1/(-v2) = m2
m2 = 350kg(0.60m/s)/[-(-0.45m/s)]
mx = 470 kg (Rounded to 2 significant figures)