A car weighing 1,600 lb travels around a curve at 70 mi/h. The next car to round this curve weighs 2,500 lb and requires the same force as the first car to keep from skidding.

Question

How fast (in mi/h) is the second car traveling? . mi/h

Answer 1

The force is directly proportional to the mass and to the square of the velocity.

So, since the force must be the same in both cases and:

F ~ 1600(70²) and F ~ 2500v² therefore

1600(70²) = 2500v²

7840000 = 2500v²

7840000/2500 = v²

3136 = v²

v = √3136 = 56 mph