Find the number of revolutions the tire makes during this motion, assuming no slipping. Answer in units of rev.

Question

A car accelerates uniformly from rest and reaches a speed of 23.9 m/s in 13.6 s. The diameter of a tire is 88.7 cm. Find the number of revolutions the tire makes during this motion, assuming no slipping. Answer in units of rev.

Answer 1

Distance s = vt/2 = πdN; N = vt/(2πd) = 23.9m/s·13.6s/2π·0.887m) = 58 rev