Stanton D. answered 12/07/23
Tutor to Pique Your Sciences Interest
Hi Elle B., Nonsense. You do so know how to solve this problem. Physics dynamics problems are either about energy or momentum. If you think about your given data, momentum (P) should seem the way to go. P(initial) = 0 b/c everything is at rest. You are given a mass and a speed for the rocket portion of P(final). That allows you to figure a momentum. That momentum MUST exactly balance the momentum of the ejected fuel. You know the "speed" of the ejected fuel, so calculate the mass.
I can see where you might have gotten alarmed because the fuel is ejected at 2.85 * 10^3 m/s, but you want the rocket ship to move at 1.25 * 10^4 m/s in the opposite direction. So the ejected fuel is trailing the rocket? Isn't the whole point of burning the fuel to get it to go far away?
Yes the ejected fuel is trailing the rocket (after a while of acceleration), as it appears to a stationary observer. But think of it this way: the fuel ejection speed operates to push the ejected fuel and the rocket apart. So you may just take the fuel momentum transfer as in the rocket's frame of reference, but the effect on the rocket as in the stationary frame of reference.
Quite a bit of fuel, isn't it.
--Cheers, --Mr. d.