What is the equation of the circle? How would i find it?

Question

Given three noncollinear​ points, there is one and only one circle that passes through them. Knowing that the equation of a circle may be written in the following​ form, find the equation of the circle passing through the given​ points, (0,4),(6,3)(-7,-3)

x^2+y^2+ax+by+c=0

the equation of the circle is x^2+y^2+()x+()y+()=0

Answer 1

Substitute the three points into the equation getting three equatios in three variables.

Then solve the system by any method.