The vertical component of the projectile’s initial velocity
vy0 = v0 sin(30°) = 40 m/s · 0.5 = 20 m/s
Three seconds later the vertical displacement of the projectile Δy will be
Δy = 20 m/s · 3 s - 1/2 ⋅ 10 m/s2 ⋅ (3 s)2 = 15 m
Emery J.
asked 12/02/23A projectile is launched with a speed of 40 m/s at an angle of 30° above the horizontal, as shown in the figure below. The projectile lands on a plateau 3 s later. The height Δy of a plateau is near
A) 15
B) 30
C) 45
The vertical component of the projectile’s initial velocity
vy0 = v0 sin(30°) = 40 m/s · 0.5 = 20 m/s
Three seconds later the vertical displacement of the projectile Δy will be
Δy = 20 m/s · 3 s - 1/2 ⋅ 10 m/s2 ⋅ (3 s)2 = 15 m
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