
Yefim S. answered 11/30/23
Math Tutor with Experience
(a) R(p) = - 6p2 + 18000p = 0; p = 0 or p = 3000;
(b) - 6p2 + 18000p > 2100000, p2 - 3000p + 350000 < 0; 121.60 < p < 2878.40
Kayla C.
asked 11/29/23Suppose that the manufacturer of a gas clothes dryer has found that when the unit price is p dollars, the revenue R (in dollars) is R(p)=−6p2+18,000p.(a) At what prices p is revenue zero?
(b) For what range of prices will revenue exceed $2100,000?
Yefim S. answered 11/30/23
Math Tutor with Experience
(a) R(p) = - 6p2 + 18000p = 0; p = 0 or p = 3000;
(b) - 6p2 + 18000p > 2100000, p2 - 3000p + 350000 < 0; 121.60 < p < 2878.40
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