Arthur D. answered 03/30/15
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P(x)=120x-x2-1000
0=-x2+120x-1000
use -b/2a or take the first derivative
-b/2a=-120/-2=60 units for x
taking the first derivative...
0=-2x+120
2x=120
x=60 again
maximum profit is -(60)2+(120)(60)-1000=-3600+7200-1000=7200-4600=$2600.00