Edward C. answered 03/30/15
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Caltech Grad for math tutoring: Algebra through Calculus
This is a ratio problem
6.022x10^23 atoms is to 12 g as X atoms is to 20.0 g
6.022X10^23 : 12 :: X : 20.0
In fraction form this is (6.022x10^23 / 12) = X / 20
Cross multiply to get
12X = 20 * 6.022x10^23
X = (20/12) * 6.022x10^23
X = (5/3) * 6.022x10^23 = 1.003666667x10^24 = 1.004x10^24 to 3 decimal places