Find all values of x in the interval [0, 2𝜋] that satisfy the equation. (Enter your answers as a comma-separated list.)

Question

16 sin²(x) = 8

Answer 1

sin^2(x)= .5

sinx= +/-sqr(.5)

x=arcsin(+/-sqr.5)= 45, 135, 225, 315 degrees= pi/4, 3pi/4, 5pi/4, 7pi/4

Answer 2

16sin²x = 8

sin²x = 1/2

sinx = ±1/√2

sinx = 1/√2 when x = π/4, 3π/4

sinx = -1/√2 when x = 5π/4, 7π/4

Answer 3

16 sin² x = 8

2 sin² x = 1

0 = 1 - 2 sin² x

0 = cos 2x

Can you complete and answer?