Heat Transfer│Please Help!

Question

When 13,140 J of heat is removed from 75 grams of metal, the temperature changes from 400. K to 200. K. What is the specific heat capacity of the metal?  

Answer 1

The amount of heat lost by the metal (q) as it cools down can be calculated using the equation:

q = mcΔT,

where m is the mass of the sample, c is the specific heat, and ΔT is the temperature change.

The equation can then be solved for the specific heat, c:

c = q/(mΔT) = 13,140 J / (75g x 200K) = 0.087J/gK

Note: ΔT = 200K