Raymond B. answered 02/19/26
Math, microeconomics or criminal justice
79 at time t=0
38 = temp in refrigerator
10 min=1/6 hr goes to 66 degrees
T(1/6) = 38 + (79-38)e^k/6=66
41e^k/6 = 66-38=28
e^k/6= 28/41
k=6ln(28/41)
T(t) = 38 +41e^tln(28/41)
Emma B.
asked 11/08/23A bottle of seltzer water initially has a temperature of 79°F. It is left to cool in a refrigerator that has a
temperature of 38°F. After 10 minutes the temperature of the seltzer water is 66°F. Use Newton's Law of Cooling, T=C+(T0−C)e^kt, to find a model for the temperature of the seltzer water, T, after t minutes.
Raymond B. answered 02/19/26
Math, microeconomics or criminal justice
79 at time t=0
38 = temp in refrigerator
10 min=1/6 hr goes to 66 degrees
T(1/6) = 38 + (79-38)e^k/6=66
41e^k/6 = 66-38=28
e^k/6= 28/41
k=6ln(28/41)
T(t) = 38 +41e^tln(28/41)
Ellsworth J. answered 11/08/23
LEARN FROM THE ONE WHO ACTUALLY TAUGHT THE CLASS!
Solved, with (hopefuly!) sufficient detail and explanation.
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