physics math help

Question

To separate a 0.19 C charge from another charge, 31 J of work is done. What is the electric potential energy of the charge?

To separate a 0.21 C charge from another charge, 31 J of work is done. What is the voltage of the 0.21 C charge?

Answer 1

The electric potential energy (U) of a charge (Q) in an electric field can be calculated using the formula:

U = Q * V

where U is the electric potential energy and V is the voltage (electric potential).

In the first scenario, to separate a 0.19 C charge, 31 J of work is done. Therefore, the electric potential energy (U) is 31 J, and the charge (Q) is 0.19 C. To find the voltage (V), rearrange the formula:

V = U / Q

V = 31 J / 0.19 C

Calculate V to find the voltage.

In the second scenario, to separate a 0.21 C charge, 31 J of work is done. The electric potential energy (U) is 31 J, and the charge (Q) is 0.21 C. To find the voltage (V), use the same formula:

V = U / Q

V = 31 J / 0.21 C

Calculate V to find the voltage in the second scenario.

Answer 2

The electric potential energy of the charge is 31 J. The voltage (also known as electric potential) is the electric potential energy per unit charge. Therefore, V = (31 J)÷(0.21 C) ≈ 150 J·C^-1.