Daniel B. answered 11/06/23
A retired computer professional to teach math, physics
Let
M = 5.97 × 1024 kg be the mass of the Earth,
m = 1.0 × 1015 kg be the mass of the asteroid,
v = 4.0 × 104 m/s be the impact speed of the asteroid,
w (to be computed) be the recoil velocity of the Earth,
R = 1.5×1011 m be the distance between the Earth and the sun,
T = 1 year ≈ π×107 s.
1.
Recoil, in general, is the consequence of conservation of momentum.
The momentum of the pair (Earth, asteroid) before the collision
must equal the final momentum of the Earth with the asteroid imbedded in it.
Before the collision the total momentum is
M×0 + m×v
After the collision the total momentum is
(M+m)× w
Setting those two equal
(M+m)w = mv
So
w = mv/(M+m) = 1.0 × 1015 × 4.0 × 104 /(5.97 × 1024 + 1.0 × 1015) = 6.7 × 10-6 m/s
2.
The velocity of the Earth around the Sun is
2πR/T = 2×π×1.5×1011/π×107 = 3×104 m/s
The ratio between the recoil velocity and the Earth's speed around the Sun is
6.7×10-6 / 3×104 = 2.2×10-10 = 2.2×10-8%