Ariel B. answered 11/03/23
PhD (Physical Chemistry), MS (Theoret.Physics), 10+ yr. tutor. exp.
"...Assume the partner’s velocity is zero at the beginning and the end of the lift..m" is the key here. The cheerleader does at each lift TWICE the work: first he'd accelerate his partner but then he'd slow him down to zero speed. So on each lift he'd do the work 2mgh. Multiply then by 29, that's all
Best,
Dr.Ariel B