
Pejman P. answered 11/03/23
Bachelor degree in Mathematics with Physics minor
By Hook's law:
F=kΔx
43.2=k(0.144)
k=43.2/0.144=300N/m
Christina B.
asked 11/03/23The force required to stretch a Hooke’s-law spring varies from 0 N to 43.2 N as we stretch the spring by moving one end 14.4 cm from its unstressed position. Find the force constant of the spring. Answer in units of N/m.
Pejman P. answered 11/03/23
Bachelor degree in Mathematics with Physics minor
By Hook's law:
F=kΔx
43.2=k(0.144)
k=43.2/0.144=300N/m
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