
William C. answered 11/02/23
Experienced Tutor Specializing in Chemistry, Math, and Physics
P(x) = x4 − 5x3 + 4x2
x2 is a common factor of all three terms so we can write
P(x) = x2(x2 − 5x + 4)
The quadratic can be factored by finding a pair of numbers
- whose sum is –5, and
- whose product is 4
That pair of numbers is –4 and –1, so we have the factored form of our polynomial:
P(x) = x2(x – 4)(x – 1)
So the zeros are
0, 4, 1
The first zero (0) has a multiplicity of 2.
[ See if you can also use the method above to find the zeroes of P(x) = x3 − x2 − 12x ]