i need help sol.ving this

Question

Factor the polynomial and use the factored form to find the zeros. (Enter your answers as a comma-separated list. Enter all answers using the appropriate multiplicities.)

P(x) = 1/7(2x4 + 3x3 − 16x − 24)2

Answer 1

P(x) = (1/7)(2x⁴ + 3x³ - 16x - 24)² = (1/7)[x³(2x + 3) - 8(2x + 3)]²

= (1/7)(2x + 3)²(x³- 8)² = (1/7)(2x + 3)²(x - 2)²(x² + 2x + 4)²

-3/2 and 2 are both roots with multiplicity 2

x² + 2x + 4 has two complex roots (that are conjugates and have multiplicity 2). These roots can be found by using the quadratic formula.