Edward C. answered 03/29/15
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Caltech Grad for math tutoring: Algebra through Calculus
Pr[A|B] = Pr[AnB] / Pr[B] = 0.1 / 0.35 = 10/35 = 2/7 ~ 0.2857
Pr[B|A] = Pr[BnA] / Pr[A] = 0.1 / 0.4 = 0.25

Edward C.
tutor
Sorry maybe I did not understand your question. (1) asks for the conditional probability of A given that B has occurred. Since B has occurred the original sample space S is restricted to B, which occurs with probability 0.35. Within the space of B,
A occurs with probability 0.1 since the probability of A and B both occurring is 0.1. So the probability of A given B is 0.1 / 0.35 = 10 / 35 = 2/7. (2) is solved in a similar way.
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03/30/15
Katie C.
it was right I was just entering it into the wrong problem. Sorry, Thanks!!
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03/30/15
Katie C.
could you help me with other problems?
Suppose for this problem that Pr[E] = [ 5/8] and Pr[F] = [ 3/4]. Just as in the book, Pr[(E ∪F)′] = 0.
(1) What is Pr[E | F]?
(2) What is Pr[F | E]?
(1) What is Pr[E | F]?
(2) What is Pr[F | E]?
Suppose for this problem that Pr[E] = [ 1/12], Pr[F] = [ 1/6], and Pr[E ∩F′] = [ 0/1].
(1) What is Pr[E | F]?
(2) What is Pr[F | E]?
(1) What is Pr[E | F]?
(2) What is Pr[F | E]?
assume that Pr[E] = 0.3, Pr[F] = 0.35, and Pr[E′∩ F] = 0.15.
Compute the following conditional probabilities:
(1) Pr[E | F] =
(2) Pr[F | E] =
Compute the following conditional probabilities:
(1) Pr[E | F] =
(2) Pr[F | E] =
Report
03/30/15
Katie C.
03/30/15