William C. answered 10/26/23
Experienced Tutor Specializing in Chemistry, Math, and Physics
m₁ = 100 kg, m₂ = 50 kg
before: total momentum = 0
after: total momentum = m₁v₁ + m₂v₂
Conservation of momentum: 0 = m₁v₁ + m₂v₂
So m₁v₁ = –m₂v₂
which means
v₂ = –(m₁/m₂)v₁ = –(100/50)v₁ = –2v₁
So the student on the right (velocity v₂)
moves backward twice as fast
as the student on the left (velocity v₁)
Answer
The right student moves backward faster than the left student