Ariel B. answered 10/24/23
PhD (Physical Chemistry), MS (Theoret.Physics), 10+ yr. tutor. exp.
Christina,
Assume the car while skidding moves with constant acceleration (actually, deceleration as it would be opposite to the velocity). That acceleration would depend only on the mass of the car and coefficient of kinetic friction between its tires and the road and therefore would not depend on the starting speed
Use a standard expression braking distance d, starting speed v0 and acceleration a
- v02=2ad so, d=v02/2a (1)
We see from (1) that d is directly proportional to v02 . Therefore comparing the 2 examples (when
(v0)1=45km/hr and (v0)2=113.5km/hr
we would get from (1)
d2/d1=[(v0)2]2/(v0)1]2=[(v0)2/(v0)1]2=(113.5/45)2=6.36 (2)
Therefore, d2=(d2/d1)d1=6.36x12m=76m (3)
(we left only 2 significant figures as that of the least accurate data given (,45km/hr and 12m)
Hope that is helpful,
Dr.Ariel B