Benson A.

asked • 10/20/23

This problem has two parts to it. I will be typing the questions for both parts and other info in "Description"

When the moon is directly overhead at sunset, the gravitational force on the Moon due to Earth, FEM, is perpendicular to the gravitational force on the Moon due to the Sun, FSM. These two forces have magnitudes FEM = 1.98 × 1020 N and FSM = 4.36 × 1020 N. Assume that all other forces are negligible. The mass of the Moon is m = 7.35 × 1022 kg.


Part a) Write an expression for the magnitude of the acceleration of the Moon.


Part b) What is the acceleration of the Moon in m/s2?

1 Expert Answer

By:

Benson A.

Thank you for the explanation. I really appreciate that. Therefore, based on your explanation would the answer for part a be, square root ((F_SM/m)^2 + (F_EM/m)^2). Then based on that as well as based on your explanation would the answer for part b be, (about) 6.52*10^-3 m/s^2.
Report

10/22/23

Justin C.

tutor
Precisely! Well done!!
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10/22/23

Benson A.

Thank you so much for the help.
Report

10/22/23

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