William C. answered 10/18/23
Experienced Tutor Specializing in Chemistry, Math, and Physics
The maximum static friction possible is μsmg cos(32°) = (0.72)(1.9)(9.8)cos(32°) ≈ 11.4 N
The gravitational force parallel to the incline is mg sin(32°) = (1.9)(9.8)sin(32°) ≈ 9.4 N which is not enough force to overcome static friction.
Since the brick is not moving, the magnitude of the static friction force acting on the brick is the same as that of the gravitational force parallel to the incline.
Answer
9.4 N