
William W. answered 10/17/23
Experienced Tutor and Retired Engineer
Draw a free-body diagram:
FN is the normal force, which is what you are solving for.
The weight (W) is the 310 N
Break the weight into two components Wy (weight in the y-direction) and WX (weight in the x-direction.
Wy = Wcos(27°) = 310cos(27°) = 276.2 N
Summing the forces in the y-direction:
∑Fy = 0 = FN - Wy therefore FN = Wy = 276.2 N Round the result to 2 sig figs. FN = 280 N