William C. answered 10/15/23
Experienced Tutor Specializing in Chemistry, Math, and Physics
The gravitational force on the truck is mg sin(θ).
To stop the parked truck from sliding, the static frictional force must be equal in magnitude.
Plug in m = 5000 kg, g = 9.8 m/s2 and θ = 7° to get
(5000)(9.8) sin(7°) = 5971.7 N
Answer (rounded to 2 significant figures)
The frictional force on the truck is 6.0 × 103 N